1.
(a)
(b)
(see part
(c))
(c)
(d)
Since
2. 12 out of 100 are dissatisfied, so 88 are satisfied.
S= the set of 4 element subsets of 100 people. n(S)
=C(100,4)
E= The event that all 4 chosen were satisfied. n(E) = C(88,4)
3.
(a)
where
OR
Let D = the event doubles are rolled and T = the event that
sum is even (try using "checkerboard" to represent the sample space)
(b)
(c)
4.
(a)
(b)
5.
(a) C(17,4)
(b) C(17,4) - C(13,4) (total # - no MD's) OR C(4,1)C(13,3) + C(4,2)C(13,2) + C(4,3)C(13,1) + C(4,4) (1 MD + 2 MD + 3MD + 4 MD)
(c) C(17,4) - C(14,4) (total - non-pilots)
(d) 11 are neither MD or pilot so C(11,4)
6.
A and B are independent so