{VERSION 3 0 "SUN SPARC SOLARIS" "3.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 }{CSTYLE "2D Comment" 2 18 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 } {CSTYLE "" -1 256 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 257 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 258 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 259 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 } {CSTYLE "" -1 260 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 261 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 262 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 263 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 } {CSTYLE "" -1 264 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 265 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 266 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 267 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 } {CSTYLE "" -1 268 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "" 0 256 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "" 0 257 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "" 0 258 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }} {SECT 0 {EXCHG {PARA 256 "" 0 "" {TEXT -1 11 "Maple Lab 7" }}{PARA 0 " " 0 "" {TEXT -1 136 "Today we will have fun with parametric and polar \+ equations. Here's how we plot polar curves in Maple. First load up t he plots package." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "with(p lots):" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 31 "To plot the polar equat ion r = " }{XPPEDIT 18 0 "theta;" "6#%&thetaG" }{TEXT -1 7 " sin (3" } {XPPEDIT 18 0 "theta;" "6#%&thetaG" }{TEXT -1 5 ") as " }{XPPEDIT 18 0 "theta;" "6#%&thetaG" }{TEXT -1 17 " varies from -10 " }{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 8 " to 10 " }{XPPEDIT 18 0 "Pi;" "6#%#PiG " }{TEXT -1 8 " , type:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 38 " polarplot(t*sin(3*t),t=-10*Pi..10*Pi);" }{TEXT -1 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 30 "In Maple, we use t instead of " } {XPPEDIT 18 0 "theta;" "6#%&thetaG" }{TEXT -1 136 " . Also, as a remi nder on how to graph parametric equations: to plot x = t + 2 sin (2t) \+ , y = t + 2 cos (5t) from t = -10 to 10, type:" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 44 "plot([t+2*sin(2*t),t+2*cos(5*t),t=-10..10]);" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 160 "Welp, that's it for the intro. Problems are a'comin'. Note that problems 1 and 3 deal with PARAMET RIC equations, while problem 2 deals with POLAR equations. " }{TEXT 266 40 "PLEASE SAVE YOUR WORKSHEET PERIODICALLY." }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 80 "1) Consider the fo llowing parametric equations: x = sin(t) , y = sin(t+sin(t)). " } {TEXT 267 65 " Find the equation of the tangent line to this curve whe n t = 0. " }{TEXT -1 34 "Do all relevant commands on Maple!" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 6 "2) a) " }{TEXT 260 24 "Graph the polar equation" }{TEXT -1 5 " r = " }{XPPEDIT 18 0 " theta;" "6#%&thetaG" }{TEXT -1 2 " " }{TEXT 261 3 "as " }{XPPEDIT 18 0 "theta;" "6#%&thetaG" }{TEXT 265 21 " ranges from 0 to 30" }{TEXT -1 3 ". " }{TEXT 262 62 "Briefly and concisely explain why the plot a ppears as it does." }}{PARA 0 "" 0 "" {TEXT -1 81 " b) Investigate \+ the family of curves defined by the polar equation r = sin(n " } {XPPEDIT 18 0 "theta;" "6#%&thetaG" }{TEXT -1 35 "), where n is a posi tive integer. " }{TEXT 263 57 "How does it seem that the number of lo ops in the graph of" }{TEXT -1 12 " r = sin(n " }{XPPEDIT 18 0 "theta ;" "6#%&thetaG" }{TEXT -1 3 ") " }{TEXT 264 30 "is related to the val ue of n? " }{TEXT -1 394 " (Hint: to try and see the relationship, jus t try graphing it for some values of n and notice a pattern. I DO NOT WANT ANY OF THESE GRAPHS PRINTED OUT TO BE HANDED IN!!! NONE!! DO YO U HEAR ME!!! If you want, you could start a new worksheet just to foo l around with the graphs. At any rate, once you see what the pattern \+ is, just explain it to me. You don't have to tell me WHY it happens.) " }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 77 "3) Th e following parametric equations define a curve known as Cormu's spira l:" }}{PARA 257 "" 0 "" {TEXT -1 11 "x = C(t) = " }{XPPEDIT 18 0 "int( cos(Pi*u^2/2),u = 0 .. t);" "6#-%$intG6$-%$cosG6#*(%#PiG\"\"\"*$%\"uG \"\"#F+\"\"#!\"\"/F-;\"\"!%\"tG" }{TEXT -1 21 " , y = S(t) = " }{XPPEDIT 18 0 "int(sin(Pi*u^2/2),u = 0 .. t);" "6#-%$intG6$-%$sinG6#* (%#PiG\"\"\"*$%\"uG\"\"#F+\"\"#!\"\"/F-;\"\"!%\"tG" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }{TEXT 257 85 "Define the functions C(t) and S(t) as abo ve. Then graph this curve from t = -5 to 5." }{TEXT -1 60 " It seems it might be converging to two different points. " }{TEXT 258 23 "To \+ check this out, find" }{TEXT -1 3 " " }{XPPEDIT 18 0 "limit(C(t),t = infinity);" "6#-%&limitG6$-%\"CG6#%\"tG/F)%)infinityG" }{TEXT -1 4 " \+ " }{TEXT 256 3 "and" }{TEXT -1 5 " " }{XPPEDIT 18 0 "limit(S(t) ,t = infinity);" "6#-%&limitG6$-%\"SG6#%\"tG/F)%)infinityG" }{TEXT -1 93 " . So we see that indeed as t gets larger, the curve gets closer and closer to the point ( " }{XPPEDIT 18 0 "1/2;" "6#*&\"\"\"\"\"\"\" \"#!\"\"" }{TEXT -1 3 " , " }{XPPEDIT 18 0 "1/2;" "6#*&\"\"\"\"\"\"\" \"#!\"\"" }{TEXT -1 99 " ) (upper right). In the same fashion, as t g ets more negative the curve approaches the point ( - " }{XPPEDIT 18 0 "1/2;" "6#*&\"\"\"\"\"\"\"\"#!\"\"" }{TEXT -1 6 " , - " }{XPPEDIT 18 0 "1/2;" "6#*&\"\"\"\"\"\"\"\"#!\"\"" }{TEXT -1 152 " ) (lower left). \+ Let a be some positive number. From the text, we know that the equat ion for the length of this curve from t = 0 to t = a is given by:" }} {PARA 258 "" 0 "" {XPPEDIT 18 0 "int(sqrt(diff(C(t),t)^2+diff(S(t),t)^ 2),t = 0 .. a);" "6#-%$intG6$-%%sqrtG6#,&*$-%%diffG6$-%\"CG6#%\"tGF1\" \"#\"\"\"*$-F,6$-%\"SG6#F1F1\"\"#F3/F1;\"\"!%\"aG" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }{TEXT 259 40 "Now evaluate the above formula in Maple \+ " }{TEXT -1 112 "(depending on how you choose to do this, you may need to use a \"simplify\" command to get a nice looking answer)." }{TEXT 268 1 " " }{TEXT -1 313 " You should find that your answer is in fact \+ a! This means that the length of the curve from t = 0 to t = a is a. \+ For example, the length of the curve from t = 0 to t = 8 billion is e qual to 8 billion. So even though the curve is bounded and converging to a point, it is \"infinitely long\" (in both directions)!" }}}} {MARK "7 8 18" 134 }{VIEWOPTS 1 1 0 1 1 1803 }